Naloge

1.

$\frac{2}{5}\cdot(\frac{4}{7}+\frac{1}{2})$

in

$\frac{2}{5}\cdot\frac{4}{7}+\frac{2}{5}\cdot\frac{1}{2}$

2.

Poišči pare.

Število poskusov:

3.

$5\cdot(\frac{2}{5}+\frac{1}{10})=$ 2

1

2

$15\frac{3}{7}\cdot(1-\frac{29}{36})=$ 3

$\frac{3}{4}\cdot(\frac{2}{3}+\frac{1}{3})=$

3

4

$(\frac{1}{5}+\frac{4}{5})\cdot\frac{1}{2}=$

1

2

4.

5.

$2\frac{1}{3}\cdot2\frac{2}{3}+\frac{1}{3}$

$2\frac{1}{3}\cdot(2\frac{2}{3}+\frac{1}{3})$

$2\frac{1}{3}+(2\frac{2}{3}\cdot\frac{1}{3})$

$2\frac{1}{3}\cdot2\frac{2}{3}+2\frac{1}{3}\cdot\frac{1}{3}$

$(2\frac{1}{3}+2\frac{2}{3})\cdot(2\frac{1}{3}+\frac{1}{3})$

$\frac{2}{5}\cdot(\frac{4}{7}+\frac{1}{2})=\frac{2}{5}\cdot1\frac{1}{14}=\frac{3}{7}$
$\frac{2}{5}\cdot\frac{4}{7}+\frac{2}{5}\cdot\frac{1}{2}=\frac{8}{35}+\frac{1}{5}=\frac{3}{7}$
Vrednosti številskih izrazov sta enaki. Velja zakon o razčlenjevanju.